10/4.9=t^2

Solution for 10/4.9=t^2 equation:

10/4.9=t^2

We move all terms to the left:

10/4.9-(t^2)=0

We add all the numbers together, and all the variables

-1t^2+10/4.9=0

We multiply all the terms by the denominator


-1t^2*4.9+10=0

Wy multiply elements

-4.9t^2+10=0

a = -4.9; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-4.9)·10
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*-4.9}=\frac{-14}{-9.8}
=1+3.5/8.16666666667
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*-4.9}=\frac{14}{-9.8}
=-1+3.5/8.16666666667
$